php - Not having any luck with preg_match -
im trying parse url last 2 / sections. need address (can that) , number(second section {ie:08078612,08248595} unless @ last , no address present {last url list example} {ie: 8274180}) optionally need last 3 digits of second numbers section.{ie 612,595,180}
im not having luck heres code far.
$url_list[] = $url; if(preg_match("/[0-9]/",substr(strrchr($url, '/'), 1))) { $url_list_mls[]= substr(strrchr($url, '/'), 2); $url_list_mls_last3[] = substr(strrchr($url, '/'), -3); } else { $url_list_mls[]= substr(strrchr($url, '/'), 1); $url_list_mls_last3[] = substr(strrchr($url, '/'), -3); } $url_list_addy[]= substr(strrchr($url, '/'), 1); example urls (part of full url endings examples)
/a019/08078612/214-n-crest-avenue /a019/08248595/111-n-elroy-avenue /a019/8274180 im trying make 3 lists, address (last section) number (second section) , last 3 numbers of second section number.
the original code way complicated. can capture of strings preg_match_all in single line. since street address part seems conditional, i've made in pattern. grouping last 3 {3} in own parenthesis can use them well. wasn't sure if a019 changed, i've included well, show how done.
<?php $uris = array("/a019/08078612/214-n-crest-avenue", "/a019/08248595/111-n-elroy-avenue", "/a019/8274180",); $pattern = "!/([a-za-z][0-9]+)/([0-9]+([0-9]{3}))/?([a-za-z0-9.-]+)?/?!"; $x=0; foreach($uris $uri){ preg_match_all($pattern,$uri,$matches); $address[$x]['scode'] = $matches[1][0]; $address[$x]['stcode'] = $matches[2][0]; $address[$x]['last3'] = $matches[3][0]; if(!empty($matches[4][0])){ $address[$x]['staddr'] = $matches[4][0]; } $x++; } print_r($address); ?> $address output
array ( [0] => array ( [scode] => a019 [stcode] => 08078612 [last3] => 612 [staddr] => 214-n-crest-avenue ) [1] => array ( [scode] => a019 [stcode] => 08248595 [last3] => 595 [staddr] => 111-n-elroy-avenue ) [2] => array ( [scode] => a019 [stcode] => 8274180 [last3] => 180 ) )
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