mysql - PHP How to filter array values -

i'm trying show in div 3 thumbnails stored in different folders.
in bd determined (with value "1") record has pictures. db:

+------+----------------+---------+--------+--------+ | id   | brand          |   php   |  ruby  |  java  | +------+----------------+---------+--------+--------+ | 1    | ford           |    1    |    0   |    0   | +------+----------------+---------+--------+--------+ | 2    | seat           |    1    |    1   |    1   | +------+----------------+---------+--------+--------+ | 3    | fiat           |    1    |    1   |    0   | +------+----------------+---------+--------+--------+ | 4    | toyota         |    1    |    0   |    0   | +------+----------------+---------+--------+--------+ | 5    | vw             |    1    |    0   |    1   | +------+----------------+---------+--------+--------+ 

selecting records:

$result = mysqli_query($connecdb,"select * brands php = '1' or ruby = '1' or java = '1' order id asc");   while($row = mysqli_fetch_assoc($result)){     $new_array[] = $row; } 

but problem is: how can select values ​​"1" , how know which?
maybe use: $row['php'] $row['java'] $row['ruby'] how filter values ​​"0"?

it looks want break array php, java, , ruby. below not tested, give idea.

$resultsarray = array(); while($row = mysqli_fetch_assoc($result)){     if($row['php'] == 1) {         $resultsarray['php'][] = $row['id'];     }     if($row['java'] == 1) {         $resultsarray['java'][] = $row['id'];     }     if($row['ruby'] == 1) {         $resultsarray['ruby'][] = $row['id'];     } } 

then loop through 2d array, grabbing name key in resultsarray.

foreach($resultsarray $language => $array) {     foreach($array $id) {         echo "url/".$language."/".$id;         echo "<br>";     } }