java - && Syntax Error AGP for Dummies -

so, learning off of android game programming dummies book, , have run problem (on page 128) i'm given code

case motionevent.action_down:       if (x > (screenw-playbuttonup.getwidth())/2 &&           x < ((screenw-playbuttonup.getwidth())/2) +                     playbuttonup.getwidth()) &&           y > (int)(screenh*0.45) &&            y < (int)(screenh*0.45) +           playbuttonup.getheight()) {               playbuttonpressed = true;           } break; 

and 4th 6th lines accompanied error "syntax error on token "&&", throw expected". have no idea on how fix this, i'd appreciate alternatives or help.

the parentheses messed up. specifically, second ) in line:

//                     -- 1 //                     v playbuttonup.getwidth()) && 

matches ( starting if condition, meaning && after not part of condition. remove ).

here's parentheses analysis:

if (x > (screenw-playbuttonup.getwidth())/2 &&   // ( = 3, ) = 2; nested level: 1     x < ((screenw-playbuttonup.getwidth())/2) +  // ( = 3, ) = 3; nested level: 1               playbuttonup.getwidth()) &&        // ( = 1, ) = 2; nested level: 0     y > (int)(screenh*0.45) &&                   // ( = 2, ) = 2; nested level: 0     y < (int)(screenh*0.45) +                    // ( = 2, ) = 2; nested level: 0     playbuttonup.getheight()) {                  // ( = 1, ) = 2; nested level: -1?!?         playbuttonpressed = true;                // total ( = 12, ) = 13     }