sql - Querying with where, having and order by together in mysql -

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i have following table...

        id      awaiting    approve decline               100       1         0         0              100       1         0         0              102       1         0         0              103       0         1         0              104       0         1         0              104       1         0         0              106       1         0         0              107       0         1         0              107       1         0         0              107       1         0         0

i have following code,...

  select count(*) total         (     select id     table1     group id     having count(*) = 2     , max(awaiting = 1) > 0     ) q

what above code count id repeated twice , @ least 1 of id awaititng=1,

but want is, want show above results repeated id listed if awaiting 1. (like id 100).

from above query, result 2 (2) id's 100 , 104, because group id.

now, how show result id's has awaiting=1, if id same (in case must have 3 list of rows)?

help please....

this should work:

select * table1  id in (select id              table1              group id              having count(*) = 2              , max(awaiting) = 1) , awaiting = 1

the results are:

╔═════╦══════════╦═════════╦═════════╗ ║ id  ║ awaiting ║ approve ║ decline ║ ╠═════╬══════════╬═════════╬═════════╣ ║ 100 ║        1 ║       0 ║       0 ║ ║ 100 ║        1 ║       0 ║       0 ║ ║ 104 ║        1 ║       0 ║       0 ║ ╚═════╩══════════╩═════════╩═════════╝

ande here is sqlfiddle demo.


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