awk - Sed: Complicated replace after pattern (on same line) -

suppose have text this:

  foobar 42                  | ff 00 00 00 00   foobaz 00                  | 0a 00 0b 00 00   foobie 00                  | 00 00 00 00 00   bar    00                  | ab ba 00 cd 00 

and want change non-00 on right hand side of | wrapped (), if on lhs of | has 00. desired result:

  foobar 42                  | ff 00 00 00 00   foobaz 00                  | (0a) 00 (0b) 00 00   foobie 00                  | 00 00 00 00 00   bar    00                  | (ab) (ba) 00 (cd) 00 

is there way of going using sed, or trying stretch beyond capabilities of language?

here's work far:

s/[^0]\{2\}/(&)/g wraps rhs values

/[^|]*00[^|]*|/ can used address command operate on valid lines

the trick formulate command executes in portion of pattern space.

this isn't line oriented, may explain why i'm having trouble getting expression works.

$ awk 'begin{ fs=ofs="|" } $1~/ 00 /{gsub(/[^ ][^0 ]|[^0 ][^ ]/,"(&)",$2)} 1' file   foobar 42                  | ff 00 00 00 00   foobaz 00                  | (0a) 00 (0b) 00 00   foobie 00                  | 00 00 00 00 00   bar    00                  | (ab) (ba) 00 (cd) 00 

in case string want search ever gets more complicated 2 0s, here's more extensible approach since doesn't require write re negates string:

$ awk '     begin{ fs=ofs="|" }     $1 ~ / 00 /{         split($2,a,/ /)         $2=""         (i=2;i in a;i++)             $2 = $2 " " (a[i] == "00" ? a[i] : "(" a[i] ")")     }     1 ' file   foobar 42                  | ff 00 00 00 00   foobaz 00                  | (0a) 00 (0b) 00 00   foobie 00                  | 00 00 00 00 00   bar    00                  | (ab) (ba) 00 (cd) 00