Batch file increment folder number -

i'm trying create batch file creates folders 1.2.0.1, 1.2.0.2,1.2.0.3, etc. fould code previous question , works needs:

@echo off setlocal enabledelayedexpansion set "basename=new_folder" set "n=0" /f "delims=" %%f in (   '2^>nul dir /b /ad "%basename%*."^|findstr /xri "%basename%[0-9]*"' ) (   set "name=%%f"  set "name=!name:*%basename%=!"  if !name! gtr !n! set "n=!name!" ) set /a n+=1 md "%basename%%n%" 

so way attempted have 2 variables, 1 holds first 3 digits 2.4.0 , other holds forth one.

set version=1.2.0 cd c:\users\build set "lastfolder=0" /f "delims=" %%f in (   '2^>nul dir /b /ad "%version%*."^|findstr /xri "%version%[0-9]*"' ) (   set "name=%%f"   set "name=!name:*%version%=!"   if !name! gtr !lastfolder! set "lastfolder=!name!" ) set /a nextfolder=lastfolder+1 md "%version%.%nextfolder%" 

but doesn't work because it's creating first folder , not ones following. can me determine issue? thanks

this create folders, if exist or not.

@echo off /l %%a in (1,1,255) md "1.2.0.%%a" 2>nul 

this should create next folder in series:

@echo off cd c:\users\build /l %%a in (1,1,20000000) if not exist "1.2.0.%%a\" md "1.2.0.%%a" & goto :done :done 

this code works - , same code above, within reason. 2 million folders seems fair number, if takes few seconds. :)

@echo off setlocal enabledelayedexpansion set version=1.2.0. cd c:\users\build set "lastfolder=0" /f "delims=" %%f in (   '2^>nul dir /b /ad "%version%*."^|findstr /xri "%version%[0-9]*"' ) (   set "name=%%f"   set "name=!name:*%version%=!"   if !name! gtr !lastfolder! set "lastfolder=!name!" ) set /a nextfolder=lastfolder+1 md "%version%%nextfolder%" pause