c++ - How to get command line of windows "open with .." function? -

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i asked question how windows "open with.." application list. here's a link question.

we can use shassocenumhandlers interface file association specific file extension, ex .png

then use iassochandler , can retrieves full path , file name of executable file associated file type(.png). ex:['paint': 'c:\\windows\\system32\\mspaint.exe', ...]

but want command line of executing mspaint.exe given image. this~ "%systemroot%\system32\mspaint.exe" "%1"

is there msdn api "open with.." command? think should have, since windows xp have ability.

use assocquerystring(..., assocstr_command, ...);

example:

tchar commandline[1024]; dword size = arraysize(commandline); assocquerystring(0, assocstr_command, _t(".txt"), 0, commandline, &size);

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