oracle - REGEXP_SUBSTR to update a table -

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i trying use regexp_substr update column in table , getting error, missing expression.

update p_table set f_name = select regexp_substr ( (select user_name                           user_info                          rowid = r_id ('user_info')), '[^ ]{1,15}', 1, 1)             dual;

when add parentheses before first select , after dual works sets rows in column same value. not need them unique cannot have them same. advice give me. 

update p_table set f_name = (select regexp_substr ( (select user_name                           user_info                          rowid = r_id ('user_info')), '[^ ]{1,15}', 1, 1)              dual);

as mentioned in @patrickmarchand comment oracle optimizes query, function called once. asktom article makes clear.

to workaround must introduce linked p_table rows function parameters force oracle call every row. example rowid p_table:

update p_table  set f_name = (       select          regexp_substr(            ( select user_name user_info             rowid = r_id ('user_info', p_table.rowid)           ),            '[^ ]{1,15}', 1, 1         )        dual     )

sqlfiddle example.


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